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A parallel plate capacitor is charged to 100 volts DC and it's plates are 1 mm...

A parallel plate capacitor is charged to 100 volts DC and it's plates are 1 mm apart, each with an area of 40x40 mm. The material between the plates has a dielectric constant of 5. Find the electric field between the plates and the value of the capacitor in microfarads.

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Answer #1

Formula used for this question is in uploaded image please go through this first-

Now-

C = 8.84*10-12 * 5 * [(40*40*10-6)] / (1*10-3)

C = 70.720 * 10-6F

For Electric feild-

E = V/d  

E = 100 / 1*10-3

E = 100*103 V/m

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