A parallel plate capacitor is charged to 100 volts DC and it's plates are 1 mm apart, each with an area of 40x40 mm. The material between the plates has a dielectric constant of 5. Find the electric field between the plates and the value of the capacitor in microfarads.
Formula used for this question is in uploaded image please go through this first-
C = 8.84*10-12 * 5 * [(40*40*10-6)] / (1*10-3)
C = 70.720 * 10-6F
For Electric feild-
E = V/d
E = 100 / 1*10-3
E = 100*103 V/m
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