Question

Suppose a function is given by y(t) = (4.85 m)sin(8.10πt). Determine the following. (Assume t is in seconds.) (a) the maximum value of y(t) m (b) the minimum value of y(t) m (c) the period of the function s

Answer 1

Sol: Here y(t) = (4.85 m)sin(8.10πt)

(a) For maximum value of y(t), the value of sin(8.10πt) should be maximum and we know the maximum value of sin(8.10πt) = 1 hence the maximum value of y(t) = 4.85 m

(b) For minimum value of y(t), the value of sin(8.10πt) should be minimum and we know the minimum value of sin(8.10πt) = -1 hence the minimum value of y(t) = -4.85 m

(c) Now if we compare given function with standered function i.e. y(t) = A sin () then we get

or

or

Hence time period T =0.247s