Question

A satellite is set to orbit at an altitude of 20200 km above the Earth's surface. What is the period of the satellite in hours? (Earth radius 6.378×1066.378×106 m, Earth mass 5.97×10245.97×1024 kg, Universal Gravitational constant G=6.67×10−11m3kg−1s−2G=6.67×10−11m3kg−1s−2 ).

Answer #1

A 345 kg satellite is orbiting on a circular orbit 8955 km above
the Earth's surface. What is the gravitational acceleration at the
location of the satellite? (The mass of the Earth is
5.97×1024 kg, and the radius of the Earth is 6370
km.)?

A 160 kg satellite is orbiting on a circular orbit 7655 km above
the Earth's surface. Determine the speed of the satellite. (The
mass of the Earth is 5.97×1024
kg, and the radius of the Earth is 6370 km.)
(in km/s)

NASA launches a satellite into orbit at a height above the
surface of the Earth equal to the Earth's mean radius. The mass of
the satellite is 830 kg. (Assume the Earth's mass is 5.97 1024 kg
and its radius is 6.38 106 m.) (a) How long, in hours, does it take
the satellite to go around the Earth once? h (b) What is the
orbital speed, in m/s, of the satellite? m/s (c) How much
gravitational force, in N,...

A. At what altitude above the Earth's surface would a satellite
have to be for it’s orbital period to be equal to 24 hours? Assume
the satellite is in a circular orbit. Assume a spherical, uniform
density for the Earth. The Earth's mass 5.98 x 10 raised to 24kg.
The Earth's radius is 6380 km B. Why would a satellite in such an
orbit be a useful thing?

Consider a 355kg satellite in a circular orbit at a distance of
3.07 x 104 km above the Earth’s surface. What is the
minimum amount of work the satellite’s thrusters must do to raise
the satellite to a geosynchronous orbit? Geosynchronous orbits
occur at approximately 3.60 x 104 km above the Earth’s
surface. The radius of the Earth and the mass of the Earth are
RE = 6.37 x 103 km and ME = 5.97 x
1024 kg respectively. The...

A satellite of mass m = 2.00 ×103 kg is launched into a
circular orbit of orbital period T = 4.00 hours. Newton's
gravitational constant is G = 6.67 ×10−11 N∙m2/kg2, and
the mass and radius of the Earth are respectively M⨁ =
5.97 ×1024 kg and r⨁ = 6.37 ×106 m. Answer the following
questions.
What is the total mechanical energy (kinetic energy + potential
energy) of the satellite in orbit? Take the gravitational potential
energy of the satellite...

A satellite is in circular orbit at an altitude of 1800 km above
the surface of a nonrotating planet with an orbital speed of 3.7
km/s. The minimum speed needed to escape from the surface of the
planet is 8.4 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
59 min.
83 min.
75 min.
67 min.
51 min.

A 200 kg satellite is placed in Earth’s orbit 200 km above the
surface. The Radius of Earth is 6.37 x 106 m, and the Earth’s mass
is 5.98 x 1024 kg.
A) Assuming a circular orbit, how long does the satellite take
to complete one orbit?
B) What is the satellite’s speed?

(a) Calculate the orbital speed of a satellite that orbits at an
altitude h = one Earth radius above the surface of the Earth. (b)
What is the acceleration of gravity at this altitude? (G = 6.67 x
10-11 N.m2 /kg2 , ME = 5.97 x 1024 kg, RE = 6.37 x 106 m)

A satellite is in circular orbit at an altitude of 1500 km above
the surface of a nonrotating planet with an orbital speed of 3.4
km/s. The minimum speed needed to escape from the surface of the
planet is 8 km/s, and G = 6.67 × 10-11 N ·
m2/kg2. The orbital period of the satellite
is closest to
A)59 min.
B)45 min.
C)72 min.
D)65 min.
E)52 min.

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