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TALLEDEGA MOTOR SPEEDWAY IN ALABAMA HAS TURNS AT 33 DEGREES. IF A RACECAR IS TRAVELLING AT...

TALLEDEGA MOTOR SPEEDWAY IN ALABAMA HAS TURNS AT 33 DEGREES. IF A RACECAR IS TRAVELLING AT 46 M/S WHAT RADIUS MUST THE TURN BE FOR THE CAR TO MAKE THE TURN WITHOUT SKIDDING?

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Answer #1

The free-body diagram for the car is drawn below.

The normal force, N, has been resolved into horizontal and vertical components. and the banking angle,

Given, velocity of car , v = 46 m/s

In Vertical direction, acceleration = 0 ,therefore

Now consider the horizontal direction,

   (Substituting value of N )

  

  

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