TALLEDEGA MOTOR SPEEDWAY IN ALABAMA HAS TURNS AT 33 DEGREES. IF A RACECAR IS TRAVELLING AT 46 M/S WHAT RADIUS MUST THE TURN BE FOR THE CAR TO MAKE THE TURN WITHOUT SKIDDING?
The free-body diagram for the car is drawn below.
The normal force, N, has been resolved into horizontal and vertical components. and the banking angle,
Given, velocity of car , v = 46 m/s
In Vertical direction, acceleration = 0 ,therefore
Now consider the horizontal direction,
(Substituting value of N )
Get Answers For Free
Most questions answered within 1 hours.