A cockroach of mass m lies on the rim of a uniform disk of
mass 6.00m that can rotate freely about its center like a
merry-go-round. Initially the cockroach and disk rotate together
with an angular velocity of 0.210 rad/s. Then the cockroach walks
half way to the center of the disk.
(a) What then is the angular velocity of the cockroach-disk system?
_____________rad/s
(b) What is the ratio K/K0 of the new
kinetic energy of the system to its initial kinetic energy?
______________
(c) What accounts for the change in the kinetic energy? (Select all that apply.)
friction
centripetal force
gravity
cockroach does negative work on the disc
centrifugal force
cockroach does positive work on the disc
Using conservation of angular momentum,
Moment of inertia of disk = I = mr2/2 = 3mr2
Initial moment of inerta of cockroach =I1= mr2
Final moment of inerta of cockroach = I2 =m(r/2)2 =mr2/4
Initial angular velocity of the system = ω1 = 0.21 rad/s
Let ω2 be the final angular velocity of the system
(a) Using conservation of angular momentum,
(I+I1)ω1 = (I+I2)ω2
=> (4mr2)(0.21) = (13/4)(mr2)ω2
=> ω2 = 0.26 rad/s
(b) Initial kinetic energy = K0 = (1/2)(I+I1)ω12 = 0.088mr2
Final kinetic energy = K = (1/2)(I+I2)ω22 = 0.109mr2
K/K0 = 1.24
(c) The cockroach does positive work on the disc
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