Question

A small, m = 2.00 g plastic ball is suspended by a L = 25.0 cm...

A small, m = 2.00 g plastic ball is suspended by a L = 25.0 cm long string in a uniform electric field, as shown in the figure below. If the ball is in equilibrium when the string makes a 12.0° angle with the vertical as indicated, what is the net charge on the ball?   µC

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Answer #1

As the figure is not provided by you, i have assumed the figure as shown as I have a lot of experience of this kind of question.

Now, for equilibrium condition, force applied on the ball should be equal so-

Mg*Sin12o = E*q*Cos12o

2*10-3 * 10 *0.208 = E*q * 0.978

as the value of E is not given, i have to leave this here only,

Put the value of E and do calculation,

you will find your answer and let me know if you have any doubts.

Thankyou !!! Have Fun

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