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In the hydrogen atom the radius of orbit B is nine times greater than the radius...

In the hydrogen atom the radius of orbit B is nine times greater than the radius of orbit A. The total energy of the electron in orbit A is -3.40 eV. What is the total energy of the electron in orbit B?

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Answer #1

In the hydrogen atom , radius = 0.529 * n2

As, the radius of orbit B is nine times greater than the radius of orbit A.

=> nB = 3 * nA

As, energy of electron = - 13.6 eV/n2

=> the total energy of the electron in orbit B = - 3.40 eV/9

                                                                       = - 0.377 eV

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