A 2 kg object undergoes simple harmonic motion with an amplitude of 0.16 m and a maximum acceleration of 5 m/s2 . Part A What is its energy?
Given that :
mass of the object, m = 2 kg
amplitude, A = 0.16 m
maximum acceleration, amax = 5 m/s2
Part-A : its energy will be given as -
E = (1/2) m vmax2 { eq.1 }
where, vmax = maximum velocity = A
then E = (1/2) m A22
{ eq.2 }
using an equation, to find the value of '' :
amax = A 2
Or 2 =
amax /
A
{ eq.3 }
inserting the value of 2 in
eq.2, we get
E = (1/2) m A2 (amax / A)
E = (1/2) m A amax { eq.4 }
inserting the values in eq.4,
E = (0.5) (2 kg) (0.16 m) (5 m/s2)
E = 0.8 J
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