Question

Three 5.0 kg spheres are distributed as follows. Sphere A is located at the origin, sphere B is located at x = 0.30 m y = 0 m, and sphere C is located at x = 0 m and y = 0.40 m. Find the net gravitational force vector that sphere A experiences.

Answer #1

**Given**

**mass of spheres**

**mA = = mB= mC = 5 kg**

**located at**

**mA at (0m,0m),mB at (0.3m,0m), mC at
(0m,0.4m)**

**we know that the graviational force between two bodies
of m1,m2 separated by a distanc d is**

** Fg = G m1*m2/d^2; G is universla gravitaional
constant = 6.674*10^-11 m3 / kg s2**

**so F AB = 6.674*10^-11*5*5/(0.3)^2 N = 1.8538899*10^-8 N,
along x -axis**

**F Ac = 6.674*10^-11*5*5/(0.4)^2 N = 1.0428125*10^-8 N,
along y- axis**

**net force is = sqrt(FAB^2+FAC^2+2*FAB*FAC*cos90)
**

** =
sqrt((1.8538899*10^-8)^2+(1.0428125*10^-8)^2+2*1.8538899*10^-8*1.0428125*10^-8*cos90)
= 2.1270556343167*10^-8 N**

**the direction is theta = arc tan
((1.0428125*10^-8)/(1.8538899*10^-8))**

** theta = 29.3577
degrees**

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