Question

Consider a 10 kg block attached to a spring whose spring constant is k 1000 N/m, originally in equilibrium. The block is then given an initial speed of 4 m/s. The maximum deviation (in meters) from equilibrium achieved by the oscillating block is closest to

Answer 1

Mass of the block = m = 10 kg

Force constant of the spring = k = 1000 N/m

Speed given to the block at the equilibrium position = V = 4 m/s

Maximum deviation of the block from the equilibrium = d

By conservation of energy the kinetic energy of the block is converted into the potential energy of the spring at maximum deviation.

d = 0.4 m

Maximum deviation of the oscillating block from the equilibrium = 0.4 m