Use Gauss’ law to find the electric field 1.6 m from a large plane of charge with a charge density of 7.4 mC/m2. Clearly indicate the shape and dimensions of your Gaussian surface as well as the amount of flux through each of its parts.
Electric field is parallel to other four surfaces therefore flux is zero
Gaussian surface is cuboid chosen such that plane of charges cut through it symmetrically. Length of cuboid is 1.6+16= 3.2 m. Cross section area is S.
Electric field through surface A and surface B is perpendicular so flux from each of them is E.S
From the result it can be noted that Electric field due to a large plane at any point is constant and is independent of distance of point from the plane.
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