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How many calories of heat are released when 245 g of water at 40.0 oC is...

How many calories of heat are released when 245 g of water at 40.0 oC is changed to steam at 130.0 oC?

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Answer #1

Mass m = 245gm

heat realesed by changing temerature of water from 40 to 100

Q1 = mC(Tf-Ti)

specific heat C = 4.182 J/gC

Q1 = 245*4.182*(100-40)

Q1 = 61475.4 J

heat realesed by changing water to steam at 100C

latent heat pf vapourization = 2230 J/gm

Q2 = mL

Q2 = 245*2230

Q2 = 546350 J

heat realesed by changing temerature of vapor from 100 to 130.

specic heat of vaour = 1.996 J/gC

Q3 = 245 * 1.996 * (30)

Q3 = 14670.6 J

total heat released = Q1 + Q2 + Q3

Qnet = 622496.1 J

Qnet = 622.5 KJ

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