Question

A finite line of charge with linear charge density ?=2.90×10−6 C/m and length ?=0.566 m is located along the ? ‑axis (from ?=0 to ?=?). A point charge of ?=−6.00×10−7 C is located at the point ?0=1.28 m, ?0=3.00 m. Find the electric field (magnitude and direction as measured from the +? ‑axis) at the point P, which is located along the ? ‑axis at ?P=10.10 m. The Coulomb force constant is ?=1/(4?/?0)=8.99×109 (N⋅m2)/C2.

Answer 1

The electric field due to a point charge 'q' located at (x₀, y₀) at a point (x_p, y_p) which is at a distance 'r' from it is given as -

Where ' is the unit vector along the line joining (x₀, y₀) and (x_p, y_p).

And the electric field due to a finite line charge can be derived as shown below -