(a)
let q be the charge by induction when the second, identical, conducting sphere that is electrically neutral is brought into contact with the first then removed the charge on the two bodies will be (q / 2) and (q / 2)
the force between them is F = 0.002 N with a seperation r = 5cm = 0.05 m
according to coulombs law we get
F = (1 / 4o) (q1q2) / (r2)
here q1 = q2
= q / 2
solve for the amount of charge (q) that was placed on the first sphere by the induction process.
(b)
q / 2
(c)
electron charge q = 16 x 10-20 C
the force will be equal and opposite the net force will be zero
(d)
this you can calculate from
F = (1 / 4o) (q1q2) / (r2)
keeping r = 2 cm and r = 3 cm and find the net force
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