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Two charges, +2 micro C & +5 micro C are 0.40 m apart. What will be...

Two charges, +2 micro C & +5 micro C are 0.40 m apart. What will be the net force on a +1 micro C charge which is placed halfway between the two charges? Note: mu= x 10-6

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Answer #1

Since all the charges are positive, every forces are repulsive.

Here the force due to 2uC will be towards right and that due to 5uC will be towards left.

Tha latter will be higher and results in the net effective force to be in the left direction.

The magnitude of force is obtained by the formula

F = (q1 × q2)÷((4 × pi × epsilon 0 ) × d^2))

Where q is the charge

d is the distance between the charges and 1÷( 4 × pi × epsilon 0) has the value 9 × 10e9.

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