Question

A -4.90 μC charge is moving at a constant speed of 6.90×10^5 m/s in the +x−direction relative to a reference frame. At the instant when the point charge is at the origin, what is the magnetic-field vector it produces at the following points.

a) x=0.500m,y=0, z=0

b) x=0, y=0.500m, z=0

c) x=0.500m, y=0.500m, z=0

d) x=0, y=0, z=0.500m

Answer in Vector Format

Answer 1

field due to moving charge is given by

B = (uo / 4pi) q ( v*× r) / r^3

B = - 10^-7* 4.9* 10^-6 ( v × r) / r^3

=========

a)

B = - 4.9* 10^-13* ( 6.9i × 0.5i)/ 0.5^3 = O T

=======

b)

B = - 4.9* 10^-13* 10^5* ( 6.9i × 0.5j) / 0.5^3

B = - 1.352* 10^-6 k T

======

c)

B = - 4.9* 10^-13* 10^5* (6.9i × ( 0.5i +0.5 j)) / (sqrt ( 0.5^2 + 0.5^2))^3

B = - 4.78* 10^-7 k T

=====

d)

B = 1.352* 10^-6 j T

======

comment before rate in case any doubt, will reply for sure.. goodluck