Question

A thin spherical shell of radius R = 13.0 cm has total charge Q = 61.0...

A thin spherical shell of radius R = 13.0 cm has total charge Q = 61.0 nC uniformly distributed on its surface.

Part A / A test particle with charge q = 10.00 nC is initially at a position r = 34.0 cm from the center of the shell. The particle moves to the surface of the shell closest to its initial position. What is the change in potential energy of the test particle as a result of this move?

Part B/ What is the potential difference between the final position of the test charge in part A and the initial position of the test charge in part A?

ΔV=Vf−Vi =?
Part D/ What is the potential difference between the center of the shell and the surface of the shell?Part C/ The test particle now moves from the surface of the charged shell to the center of the shell. What is the change in potential energy of the test particle as a result of this 13.0 cm move?

ΔV=Vcenter−Vsurface =?

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