Question

QUESTION 1 Imagine a mass hanging from a vertical spring. When the spring is at its...

QUESTION 1

Imagine a mass hanging from a vertical spring. When the spring is at its maximum extension, which of the following can we say about the energy of the system?

A.

All of the energy of the oscillation is in thermal energy.

B.

All of the energy of the oscillation is in kinetic energy of the mass.

C.

None of the energy of the oscillation is in potential spring energy.

D.

All of the energy of the oscillation is in potential spring energy.

QUESTION 2

The frequency and period of a simple harmonic oscillator made up of a spring and a mass depends on which of the following parameters:

A.

The amount of force used to start the oscillation.

B.

The spring constant of the spring used.

C.

The amplitude of the oscillation.

D.

The length of the spring used.

QUESTION 3

The frequency and period of a pendulum that is undergoing simple harmonic motion depends on which of the following parameters?

A.

The length of the pendulum.

B.

The initial speed of the pendulum.

C.

The initial height of the pendulum displaced from equilibrium.

D.

The mass of the pendulum.

Please make sure you give the right answer

Thank you

Homework Answers

Answer #1

Q1.

When the spring is at the max extension, then velocity of mass will be zero, So at that time kinetic energy (m*V^2/2) will be zero. Now Since total energy during the motion remains constant, And

Total energy (TE) = kinetic energy (KE) + potential energy (PE)

Since KE = 0, So at this moment

Total energy will be equal to total potential energy, So

Correct option is D.

Q2.

Time period of simple harmonic oscillator made up of a spring and a mass is given by:

T = 2*pi*sqrt (m/k)

frequency is given by:

f = (1/(2*pi))*sqrt (k/m)

So from above we can see that Period and frequency depends on the mass and spring constant.

Correct option is B.

Q3.

Time period of a pendulum that is undergoing simple harmonic motion is given by:

T = 2*pi*sqrt (l/g)

l = length of pendulum

frequency is given by:

f = (1/(2*pi))*sqrt (g/l)

So from above we can see that Period and frequency depends on the length of pendulum and gravity at that place.

Correct option is A.

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