A proton and an electron are fixed in space with a separation of 815 nm. Calculate the electric potential at the midpoint between the two particles.
potential:
Find the magnitude of the electric field at the same point. magnitude of field: N/C
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a)
Charge of proton qp=1.6*10-19 C
Charge of electron qe=-1.6*10-19 C
Electric potential due to point charge is given by
V=KQ/r
Net Electric potential at midpoint between the two charges is given by
VNet=KQ1/r1 +KQ2/r2 =(9*109)(1.6*10-19)[1/(815*10-9/2) -1/(815*10-9/2)]
VNet=0 Volts
b)
Electric field due to point charge is given by
E=KQ2/r2
Magnitude of electric field at midpoint
Enet=K|Q1|/r12+K|Q2|/r22 =(9*109)(1.6*10-19)[1/(815*10-9/2)2 + 1/(815*10-9/2)2]
Enet=17343.52 N/C
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