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19.       A sign (mass = 45.0 kg) is supported by two wires. a. Find the tension...

19.       A sign (mass = 45.0 kg) is supported by two wires.

a. Find the tension in each of the wires.   

            b.         Suppose the wire on the right has a cross-sectional area of 1.20 x 10-6 m2 and is made of steel (Young's modulus = 2.00 x 1011 Pa). If it was .950 m long before it was used

                        to hold up the sign, HOW MUCH LONGER is it now?

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Homework Answers

Answer #1

Solution:

mass m= 45.0Kg

Take

a) Let the tension on the wire be T. Weight mg is acting downwards.

We have,

  

b) The Tension T in the wire causes it to strech. The orginal length of the wire is The wire has an area of cross section . Young's modulus of steel is .

The change in length of the wire is given by,

  

New length is given by

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