Question

find the mass defect the total binding energy and the binding energy per nucleon of 28 Ni 62 which has the highest binding energy per nucleon of all nuclides the neutral atomic mads of is 61.928345 u) you may use speed of lifht in vacuum)^2 = 931.5 MeV/u

Mh= 1.007825 u, mn 1.008665 u

Answer 1

Answer:

Given that, M = 61.928345 u, mass of proton m_p = 1.007825 u and mass of neutron m_n = 1.008665 u

For Ni₂₈⁶², number of proton p = 28, number of neutrons n =34

Mass defect m = [M - (pm_p + nm_n) ] = [61.928345 u - (28 x 1.007825 u) - (34 x 1.008665 u)] = 0.585365 u.

and Binding energy E = m c² = (0.585365 u) c²

we know that 1 u = 931.5 MeV/c²

Therefore, E = (0.585365) (931.5) MeV = 545.26 MeV.

Binding energy per nucleon is E/(p+n) = 545.26 MeV/(28+34) = 8.79 MeV.

answered by: anonymous