Question

A projectile (mass = 0.25 kg) is fired at and embeds itself in a stationary target...

A projectile (mass = 0.25 kg) is fired at and embeds itself in a stationary target (mass = 2.28 kg). With what percentage of the projectile's incident kinetic energy does the target (with the projectile in it) fly off after being struck?

Homework Answers

Answer #1

Let the Initial velocity of the projectile = u
Mass of projectile, m = 0.25 kg
Mass of target, M = 2.28 kg

Let the final velocity of the system be v.
Mass of the system = m + M = 2.53 kg

Apply the Principle Of Conservation of Momentum :
mu + 0 = (m + M)v
v = mu / (m + M)

Initial K.E. of the system = K.E. of projectile + K.E. of target = 1/2*mu^2 + 0 = 1/2*mu^2
Final K.E. of the system = 1/2*(m + M) v^2 = 1/2*m^2*u^2 / (m + M)

% of KE carried by the system = KE of system / KE of projectile * 100
= 100m / (m + M) = 9.88 %

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A projectile (mass = 0.30 kg) is fired at and embeds itself in a stationary target...
A projectile (mass = 0.30 kg) is fired at and embeds itself in a stationary target (mass = 2.15 kg). With what percentage of the projectile's incident kinetic energy does the target (with the projectile in it) fly off after being struck? _____ %
A projectile with a mass of 0.270 kg is fired at and embeds itself in a...
A projectile with a mass of 0.270 kg is fired at and embeds itself in a stationary target with a mass of 2.79 kg. The target and embedded projectile fly off after being struck. Determine the percent of the projectile's incident kinetic energy carried off by the target-projectile combination.
A 0.0200 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500...
A 0.0200 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500 kg block. (a) What is their velocity just after the collision? m/s (b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity? m/s (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping? m
A 0.0220 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500...
A 0.0220 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500 kg block. (a) What is their velocity just after the collision? m/s (b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity? m/s (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping? m
A bullet of mass m = 2.40×10-2 kg is fired along an incline and embeds itself...
A bullet of mass m = 2.40×10-2 kg is fired along an incline and embeds itself quickly into a block of wood of mass M = 1.35 kg. The block and bullet then slide up the incline, assumed frictionless, and rise to a height H = 1.35 m before stopping. Calculate the speed of the bullet just before it hits the wood.
A projectile of mass 2 kg is fired at an angle to the ground such that...
A projectile of mass 2 kg is fired at an angle to the ground such that its flight is parabolic. At a certain point in its flight, its potential energy is 150 J and its kinetic energy is 250 J. What is the speed of the projectile when it hits the ground? You may assume that the potential energy at ground level is zero and there is no air resistance?
A bullet of mass 1.4×10−3 kg embeds itself in a wooden block with mass 0.987 kg...
A bullet of mass 1.4×10−3 kg embeds itself in a wooden block with mass 0.987 kg , which then compresses a spring (k = 130 N/m ) by a distance 5.5×10−2 m before coming to rest. The coefficient of kinetic friction between the block and table is 0.46. a)What is the initial speed of the bullet? b)What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between the...
A bullet of mass 2.0×10−3 kg embeds itself in a wooden block with mass 0.991 kg...
A bullet of mass 2.0×10−3 kg embeds itself in a wooden block with mass 0.991 kg , which then compresses a spring (k = 200 N/m ) by a distance 3.5×10−2 m before coming to rest. The coefficient of kinetic friction between the block and table is 0.52. a)What is the initial speed of the bullet? b)What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between the...
A projectile of mass 2.0 kg is fired in the air at an angle of 43.0°...
A projectile of mass 2.0 kg is fired in the air at an angle of 43.0° to the horizon at a speed of 44.0 m/s. At the highest point in its flight, the projectile breaks into three parts of mass 1.0 kg, 0.7 kg, and 0.3 kg. The 1.0 kg part falls straight down after breakup with an initial speed of 14.8 m/s, the 0.7 kg part moves in the original forward direction, and the 0.3 kg part goes straight...
A rifle bullet with mass 15.0 g strikes and embeds itself in a block of mass...
A rifle bullet with mass 15.0 g strikes and embeds itself in a block of mass 1.500 kg that rests on a frictionless, horizontal surface and is attached to a coil spring. The spring was relaxed at the beginning. The spring constant is 550 N/m. The initial velocity of the bullet was 700 m/s. The impact compresses the spring by x (see figure below). 1) Find the magnitude of the block's velocity (with the bullet stuck inside) after the impact...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT