Question

consider a simple pendulum in simple harmonic motion () is placed on the moon, where the gravitional acceleration is 1.63 m/sec2, the increased period is T = 4.59 sec

Determine:

a. suppose that the pendulum has friction where the amplitude became 0.100 of the original amplitude after 0.001 hour. calculate the damping factor.

b. calculate the period of the pendulum with friction.  

Answer 1

Firstly, if we set a simple pendulum in SHM on moon, we are gonna observe that the gravity on earth is 6times more than that of moon.

g moon = 1/6th of g

considering the formula of time period of pendulum :

• T=2 pi under root L/g

SINCE, force of gravity is less on the moon, the pendulum will swing on slower rate.

Also, damping effect of pendulum will also reduce due to the absence of air resistance.

but time period will bound to increase because g_m=1/6g_{e leading to less frequency.}

a). DAMPING FACTOR = d / under root (2pi)² + d²

^{b) gm=1.63m/s2 ,}

^{Tm=4.59 sec}

Te can be calculated.

answered by: anonymous