Question

Find the cost of electricity for your house/your parents house/some suitable house. If you have trouble with this, use the cost as 12¢ per kilowatt- hour. Then, assuming resistive heating with a one-to-one ratio between electric power in and heat produced, find the cost of heating this house for the month of January.

Answer 1

Solution

Let us go to the basics first.

This question is based on the following concepts

1. Wattage of Heating system

2. No. of hours in the month of January

The detailed solution is described below

Let us assume that the heating system being used to heat the house:

1. Utilizes resistive heating

2. the wattage of Heating system is 5 KW

In the month of January:

Number of hours

= 31days * 24 hours/day

= 744 hours

No. of units of electricity consumed

= 5 KW * 744 hours

= 3720 KWH

Given that cost of 1 KWH = 12 cents / KWH

Cost of electricity for house

= No. of units * per KWH cost

= 3720 KWH * 12 cents / KWH

= 44640 cents

= $ 446.40 (Answer)

Note: This answer will vary from case to case depending on the wattage of Heating system chosen. In our case we have chosen 5KW heating system.

Thank you !!!