Question

# 6. A ray of light travels from a transparent material to air. The beam is refracted...

6. A ray of light travels from a transparent material to air. The beam is refracted at an angle of 25º to the normal. The beam travels at a speed of 2.20 x 108 m/s in the material. Determine the angle of incidence.

7. A ray of light travels from a transparent material to air. The beam is refracted at an angle of 25º to the normal. The beam travels at a speed of 2.20 x 108 m/s in the material. Determine the total internal reflection angle.

8. A 3.0 cm high object is placed in front of a biconvex lens with a focal length of 20.0 cm. The image is formed 35.0 cm from the vertex. Determine the position of the object in centimeters.

10. A 3.0 cm high object is placed in front of a biconvex lens with a focal length of 20.0 cm. The image is formed 35.0 cm from the vertex. Determine the height of the image in centimeters.

6.

As speed is given in the material, so refractive index of material (n) = c/v = 3×10^8/2.2×10^8

= 1.36

n1 = 1, n2 = 1.36, r = 25

So by snell's law

Sini/Sinr = n2/n1

Sini/Sin25 = 1.36/1

i = 35.2 degree

7.

As refractive index (n) = 1.36

Then by snell's law

Sini/Sinr = n2/n1

Sinθc/Sin90 = 1/1.36

θc = 47.17 degree

8.

Focal length (f) = 20 cm

Image distance (V) = 35 cm

By lens formula

1/v - 1/u = 1/f

1/35 - 1/u = 1/20

u = - 46.67 cm

This is the object distance from mirror.

9.

By magnification = hi/ho = v/u

hi/(3) = 35/(-46.67)

hi = 2.25 cm

This is the height of the image.

If you any doubts regarding this feel free to ask.

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