Question

The phase angle of an LRC series circuit with a capacitive reactance of 200 Ω, a...

The phase angle of an LRC series circuit with a capacitive reactance of 200 Ω, a resistor of 100 Ω and a certain inductor at 1000 Hz is 40.0°. What is the value of the inductance in this circuit?

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Answer #1

Phase angle, = tan-1[(XL - XC) / R]
Where XL and XC are the inductive and capacitive reactances, R is the reisistance.
tan = (XL - XC) / R
XL - XC = R * tan
XL = XC + R * tan
Substituting values,
XL = 200 + 100 * tan(40)
= 283.91 Ohm

XL = * L
Where = 2 * f, f being the frequency and L is the inductance.
L = XL /
= 283.92 / [(2 * 1000)
= 4.52 * 10-2 H

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