Question

Block A in the figure (Figure 1) hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.10 kg ; the mass of the liquid is 1.85 kg . Balance D reads 3.55 kg and balance E reads 7.50 kg . The volume of block A  is 3.50×10⁻³ m3 .

What will the balance E read if block A is pulled up out of the liquid?

Express your answer in kilograms.

Answer 1

ANSWER::

Lets, Mass of the beaker m_b = 1.10 kg

  the mass of the liquid is m_l =1.85 kg

Reading on the balance D when the object is suspended in the liquid R_{d =} 3.55 kg

Reading on the balance E on which the beaker and liquid in which the object is suspended RE = 7.50 kg

  Volume of the block A, V=3.50×10⁻³ m3

and Acceleration due to gravity, g=9.8 m/s²

When the object is pulled out of the liquid, the balance E will read the actual mass of the beaker and liquid.

So the reading of balance E is is,

  

  

  the balance E read if block A is pulled up out of the liquid is = 2.95 kilograms