Question

A stone is catapulted at time t = 0, with an initial velocity of magnitude 18.6 m/s and at an angle of 37.0° above the horizontal. What are the magnitudes of the

(a) horizontal and

(b) vertical components of its displacement from the catapult site at t = 1.01 s? Repeat for the

(c) horizontal and

(d) vertical components at t = 1.76 s, and for the

(e) horizontal and

(f) vertical components at t = 5.11 s. Assume that the catapult is positioned on a plain horizontal ground.

Answer 1

As we know that

Horizontal and vertical movement are independent of each other so we can solve them one at a time with triangle.
Hypotenuse: 18.6 m/s

x ===>cos 37 = x/18.6
0.79863551 = x/18.6
x= 14.85462049 m/s

y===> sin 37 = y/18.6

y= 11.19375943 m/s

d = vt

dx = 14.85462049 * 1.01 = 15.00316669 m @ t=1.01s

dx = 14.85462049 * 1.76 = 26.14413206 m @ t=1.76s

dy = 11.19375943*1.01 = 11.30569702 m @ t = 1.01

dy = 11.19375943*1.76 = 19.7010166 m @ t = 1.76