Question

A projectile is launched from a point on level ground with initial speed 14.5 miles/hour and initial angle of 32.2 degrees above the horizontal. Calculate the time of flight of the projectile in seconds. [Note: Don't forget to convert units as needed.]

Answer 1

1 mile = 1609.344 meter

1 hour = 3600 sec

Gravitational acceleration = g = 9.81 m/s²

Initial speed of the projectile = V = 14.5 miles/hour

Converting the speed to meter/sec,

V = 6.482 m/s

Angle at which the projectile is launched = = 32.2^o

Time of flight of the projectile = T

Time of flight for a projectile is given by,

T = 0.933 sec

Time of flight of the projectile = 0.933 sec