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a man (mass=7- kg) and a woman (mass=60kg) are standing at rest on a frictionless surface...

a man (mass=7- kg) and a woman (mass=60kg) are standing at rest on a frictionless surface holding opposite ends of the same rope. Then, the man pulls on the rope so that there is a tension in the rope. If the tension in the rope is 100 N, what is the acceleration of the center of mass of the man-woman system?

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Answer #1

Remember Newton's 2nd law FOR A SYSTEM of particles (in this case, composed by the two persons):

In particular, for the horizontal axis:

Where is the horizontal acceleration of the Center of Mass.

since there is no horizontal force (we are told that there is no friction), .

You might ask, what about the tension? Since it's an internal force for this system, it is not considered. This is true for systems. How do you know it's internal? because it's an interaction between parts of the same system: This tension acts from one person ON the other (both being part of the same system), and viceversa.

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