What is the pressure difference on your 0.5cm2 eardrum when you are 3.4 meters below the surface of a body of water? Assume the pressure difference was zero before your dive into the water?
Pressure P = Pa + gh
where Pa = 1 atm. pressure = 1.013 105 Pa
= density of water = 1000 kg/m3
g = acceleration due to gravity = 9.8 m/s2
h = height of water column = 3.4 m
Let us assume , before entering water , pressure difference is zero means,
internal pressure of ear drum is at atmospheric pressure
Hence pressure difference = P - Pa = gh = 1000 9.8 3.4 = 3.332 104 Pa
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