Use conservation of energy to determine the angular speed of the spool shown in the figure below after the 3.00-kg bucket has fallen 3.50 m, starting from rest. The light string attached to the bucket is wrapped around the spool and does not slip as it unwinds.
Conservation of energy leads to
when bucket fallen through a distance , gravitational
potential energy is converted into
kinetic energy, here kinietic energy is sum of rotational and
translationsl kinetic energy
mgh = (1/2 mv^2 + 1/2 I W^2)
then acceleration of the
a = g[1 - m/(m + 2M)] where M is the falling mass and m is
the spool mass.
a = 9.8*[1 - 5/(5+2*3)] = 5.345 m/s²
Vb = √(2ay) = 6.1168 m/s
w = Vb/R = 6.1168/.6 = 10.195 rad/se
angular speed of the spool is 10.915 rad/s
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