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When a particular inductor is connected to a sinusoidal voltage with a 141 V amplitude, a...

When a particular inductor is connected to a sinusoidal voltage with a 141 V amplitude, a peak current of 8.4 A appears in the inductor. What is the maximum current if the frequency of the applied voltage is doubled? AnswWhat is the inductive reactance at the new frequency? Answer in units of Ωer in units of A.

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Answer #1

inductive reactance = 2 * pi * frequency * inductance

If the frequency is doubled, then the inductive reactance is doubled.

by ohm's Law

voltage = current * reactance

141 = 8.4 * reactance

reactance = 16.785 ohm

If the Voltage is CONSTANT and the Reactance is DOUBLED (by the frequency being doubled), then the Current will down by HALF.

reactance at new frequency = 2 * 16.785

reactance at new frequency = 33.570 ohm

again by ohm's law

141 = I * 2 * 16.785

current = 4.2 A

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