An LR circuit is hooked up to a battery as shown in the figure, with the switch initially open. The resistance in the circuit is R=120 Ω, the inductance is L=4.90 H, and the battery maintains a voltage of E=37.0 V. At time t=0 the switch is closed.
(A)What is the current through the circuit after the switch has been closed for t=5.31E-2 s?
(B)What is the voltage across the inductor after the switch has been closed for t= 5.31E-2 seconds?
(C)What is the the power dissipation in the resistor at t=5.31E-2 seconds?
(D)How much energy is stored in the inductor at t= 5.31E-2 seconds
(E)How much work has the battery done from the time the switch was closed until t=5.31E-2 s?
(F)How much energy has been dissipated in the resistor from the time the switch was closed until t= 5.31E-2 seconds?
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