Part 1- Three charges are placed along axis x with coordinates x = 0 m, x= 0.4 m, x = 1.0 m . If q = 5nC find the direction and magnitude of the electric field at the following points: a) x = - 0.1 m; b) x = 0.3 m,.
Part 2- To solve this problem I used the formula: A. E = V/d; B. E =(kq)/r C. E = (kq1q2)/r2 D. E = (kq)/r
U can also use the formula of electric field i.e option no A )
It will result into Kq /r^2
So to find the net electric field ont he given points .use the formula also making the vectors addition rule by keeping their direction into mind.
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