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if a 35% efficient carnot engine is run in reverse to form a refrigerator, what is...

if a 35% efficient carnot engine is run in reverse to form a refrigerator, what is its COP(COEFFICIENT OF PERFORMANCE)?

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Answer #1

The efficiency of carnot engine is e = 35% = 0.35

The coefficient of performance is COP = QL/(QH - QL)

The efficiency of carnot engine is e = W/QH

Thus, the relation between efficiency and COP is,

  e = 1 / (k + 1)

                      k+1 = 1/e

                         k = (1/e)-1

                            = (1/0.35) - 1

                            = 1.85

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