Question

While hiking through the desert, you find that you are breathing deeply. Each breath you exhale...

While hiking through the desert, you find that you are breathing deeply. Each breath you exhale approximately 3.0 g of air. The air you inhale is is at 25 ∘C at 10% relative humidity. When you exhale the air is at 100% relative humidity at a temperature of 36 ∘C. How many grams of water do you lose each breath?

How much water (L) must you drink each hour if your breathing rate is 3.0×101 breaths per minute?

Homework Answers

Answer #1

Tin = 298 K (25 C) Tout=309 K (36 C)

Moles of air= 3/28 (molecular wt of air=28)

Patm=101325 pa

Ps-> Saturation pressure

Patm=101325 atm-> Atmospheric pressure

For case of inhaling air

Ps= 10% of Patm => Ps=0.1*101325 atm

Applying ideal gas equation

Ps Vin = R * n * T

Vin (inlet volume) = ( 8.314 * (3/28) * (298) )/ (0.1 *101325)

Vin (inlet volume)= 0.0262 m^3

For case of exhaling air

Ps=1 * Patm = 101325 atm

Applying ideal gas equation

Ps Vo = R * n * T

Vo (outlet volume) = ( 8.314 * (3/28) * (309) )/ (1 *101325)

Vo (oulet volume)= 0.0027 m^3

Net volume lost in 1 breathe = (0.0262-0.0027) m^3

Net volume in litres lost = 0.0235 * 0.001 litres

Water to be drank each hour= 3.0 *101 * 0.0235 * 0.001 * 60= 0.4272 L

Answer= 0.4272 L

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