Question

A laboratory electromagnet produces a magnetic field of magnitude 1.60 T. A proton moves through this field with a speed of 6.12 ? 10⁶ m/s.

(a) Find the magnitude of the maximum magnetic force that could be exerted on the proton.
N

(b) What is the magnitude of the maximum acceleration of the proton?
m/s²

(c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (Assume that the electron is moving in the same direction as the proton.)

YesNo   

Explain.

This answer has not been graded yet.

(d) Would the electron undergo the same acceleration?

YesNo   

Explain.

Answer 1

a)

maximum magnetic force ,

Fm = B*v*q

Fm = 1.60 * 6.12 *10^6 * e

Fm = 1.569 *10^-12 N

maximum magnetic force is 1.569 *10^-12 N

b)

using second law of motion

F = m * a

a = 1.569 *10^-12/1.67 *10^-27

a = 9.38 *10^14 m/s^2

the magnitude of the maximum acceleration of the proton is 9.38 *10^14 m/s^2

c)

Yes , the magitude of force will be same but the direction of force will be oposite.

d)

Now, as the mass of electron is much less than mass of electron ,

No, the acceleration of electron is different