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A 50-pF capacitor and a 200-pF capacitor are both charged to 1.70 kV. They are then...

A 50-pF capacitor and a 200-pF capacitor are both charged to 1.70 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate.

(a) Find the resulting potential difference across each capacitor.

V50 pF = kV

V200 pF = kV

(b) Find the energy lost when the connections are made.

µJ

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