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A space shuttle is in a circular orbit at a height of 250km, where the acceleration...

A space shuttle is in a circular orbit at a height of 250km, where the acceleration of Earth’s gravity is 93% of its surface value. What is the period of its orbit?

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Answer #1

Radius of Earth,

Altitude of the satellite, h= 2.5*105m

Radius of Orbit, R=Re + h = 6.6281*106m

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Centripetal acceleration,

Given that the acceleration of Earth’s gravity is 93% of its surface value.

0.93g = v2 /R

0.93g*R = v2

0.93 * 9.81m/s2 * 6.6281*106m = v2

Orbital velocity, v=7776.255 m/s

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Orbital velocity,

T =( 2** 6.6281*106 )/7776.255m/s

T= 5355.48s

ANSWER: 1.4876 hr

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