The volume of a gas is halved during an adiabatic compression that increases the pressure by a factor of 2.5. 
Part A What is the specific heat ratio γ?

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Part B
By what factor does the temperature increase?
Specific heat ratio =
Initial pressure of the gas = P_{1}
Initial volume of the gas = V_{1}
Initial temperature of the gas = T_{1}
Final pressure of the gas = P_{2} = 2.5P_{1}
Final volume of the gas = V_{2} = 0.5V_{1}
Final temperature of the gas = T_{2}
The process is adiabatic therefore,
Taking log on both sides,
= 1.32
For an ideal gas,
T_{2} = 1.25T_{1}
A) Specific heat ratio = 1.32
B) Factor by which the temperature increases = 1.25
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