Question

The coordinates of a point moving in the plane are given as x = 4t- (5t.t),...

The coordinates of a point moving in the plane are given as x = 4t- (5t.t), y = (- 3t.t) (4t.t.t) in x, y meters and t seconds.

a)

t = 2 seconds, coordinates and location vector,

b)

average speed and acceleration during the first 2 seconds,
c)
Find the moment velocity and acceleration at t = 2 seconds.
Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The coordinates of an object moving in the xy plane vary with time according to the...
The coordinates of an object moving in the xy plane vary with time according to the equations x 5 25.00 sin vt and y 5 4.00 2 5.00 cos vt, where v is a constant, x and y are in meters, and t is in seconds. (a) Determine the components of velocity of the object at t 5 0. (b) Determine the components of acceleration of the object at t 5 0. (c) Write expressions for the position vector, the...
A 3.25 kg object is moving in a plane, with its x and y coordinates given...
A 3.25 kg object is moving in a plane, with its x and y coordinates given by x = 4t2-1 and y = 4t3 + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.00 seconds.
A 2.80-kg object is moving in a plane, with its x and y coordinates given by...
A 2.80-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 2t3 + 3, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.45 s.
The horizontal coordinates of a Frisbee™ in a strong wind are given by x = -12t...
The horizontal coordinates of a Frisbee™ in a strong wind are given by x = -12t + 4t 2 and y = 10t – 3t 2 , where x and y are in meters, and t is in seconds. What is the magnitude of acceleration of the Frisbee at t = 1.0s? a) 2 m/s2 b) 10 m/s2 c) 5.7 m/s2 d) 10.6 m/s2
Maggie is moving in an xy-plane, with coordinates in meters. She moves at the constant speed...
Maggie is moving in an xy-plane, with coordinates in meters. She moves at the constant speed of of 6 meters per second.She starts at the point (12,3) and heads toward the y axis along the line y=1/3x-1. A. Give Maggies parametric equations of motion. B. Give an expression for the distance from Maggie's location to the origin t second after she starts moving.
The position of a particle moving with constant acceleration is given by x(t) = 4t2 +...
The position of a particle moving with constant acceleration is given by x(t) = 4t2 + 3t + 4 where x is in meters and t is in seconds. (a) Calculate the average velocity of this particle between t = 2 seconds and t = 7 seconds. (b) At what time during this interval is the average velocity equal to the instantaneous velocity? (c) How does this time compare to the average time for this interval? a. It is larger....
The position ? of a particle moving in space from (t=0 to 3.00 s) is given...
The position ? of a particle moving in space from (t=0 to 3.00 s) is given by ? = (6.00?^2− 2.00t^3 )i+ (3.00? − ?^2 )j+ (7.00?)? in meters and t in seconds. Calculate (for t = 1.57 s): a. The magnitude and direction of the velocity (relative to +x). b. The magnitude and direction of the acceleration (relative to +y). c. The angle between the velocity and the acceleration vector. d. The average velocity from (t=0 to 3.00 s)....
The position of a particle moving with constant acceleration is given by x(t) = 2t2 +...
The position of a particle moving with constant acceleration is given by x(t) = 2t2 + 8t + 4 where x is in meters and t is in seconds. (a) Calculate the average velocity of this particle between t = 6 seconds and t = 9 seconds.   (b) At what time during this interval is the average velocity equal to the instantaneous velocity?   
The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^,...
The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^, where a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector r→=(19.0m)i^+(44.0m)j^ locates the particle, which then has the velocity vector v→=(5.40m/s)i^+(1.70m/s)j^. At t = 4.10 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?
The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove...
The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove a With right-arrow equals 4t ModifyingAbove i With caret plus 5t ModifyingAbove j With caret, where ModifyingAbove a With right-arrow is in meters per second-squared and t is in seconds. At t = 0, the position vector ModifyingAbove r With right-arrow equals left-parenthesis 24.0mright-parenthesis ModifyingAbove i With caret plus left-parenthesis 49.0mright-parenthesis ModifyingAbove j With caret locates the particle, which then has the velocity vector...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT