Question

A 10.7-V battery, a 4.91-Ω resistor, and a 10.7-H inductor are connected in series. After the current in the circuit has reached its maximum value, calculate the following. (a) the power being supplied by the battery (b) the power being delivered to the resistor (c) the power being delivered to the inductor (d) the energy stored in the magnetic field of the inductor

Answer #1

(a) when current in the circuit has reached its maximum value

so

P=E^{2}/R

P= 10.7^{2} / 4.91

P= 23.31 W;

(b) when the current in the circuit has reached its maximum value

P=E^{2}/R

P= 10.7^{2} / 4.91

P= 23.31 W;

(c) After the current in the circuit has reached its maximum value
:

so

as there is no potential difference between inductors ends

so P= 0

(d) After the current in the circuit has reached its maximum value this value is

I=E/R

I = 10.7/4.91 = 2.17 amp;

energy will be U=1/2 x L x I^{2}

U= 1/2 x 10.7x 2.17^{2} =25.19 J

A 11.0-V battery, a 5.08-Ω resistor, and a 10.2-H inductor are
connected in series. After the current in the circuit has reached
its maximum value, calculate the following.
(a) the power being supplied by the battery
_______W
(b) the power being delivered to the resistor
_______W
(c) the power being delivered to the inductor
_______W
(d) the energy stored in the magnetic field of the inductor
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respectively.
(a) Find the energy stored in the inductor when the current
reaches its maximum value.
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(b) Find the energy stored in the inductor one time constant after
the switch is closed.

A 24 V battery is connected in series with a resistor and an
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coil has a resistance of 1.70 Ω.
What is the maximum current after the switch is closed?
How long does it take for the current to reach 1/2
maximum?
How much energy is stored in the coil?

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supply (battery) connected in
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i. What is the total energy stored in the capacitor when it reached
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ii. What is the total energy supplied by the power supply during
this time?
iii. Does the capacitor store the total energy supplied by the
battery? Otherwise, explain how
the energy supplied by the battery used in the circuit.

A 11.0-Ω resistor, 6.00-mH inductor, and 70.0-µF capacitor are
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period.

A 10.5-Ω resistor, 6.50-mH inductor, and 130-µF capacitor are
connected in series to a 55.0-V (rms) source having variable
frequency. If the operating frequency is twice the resonance
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connected in series with an open switch. The switch is suddenly
closed.
1)How long after closing the switch will the current through the
inductor reach one-half of its maximum value?
Express your answer in microseconds.
2)How long after closing the switch will the energy stored in
the inductor reach one-half of its maximum value?
Express your answer in...

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Answer in mJ

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