In an RC circuit, if we changed the resistance to one with a higher value, we would expect that:
The area under the curve change
Capacitor discharges faster
Capacitor takes longer to achieve Qmax
Changes the voltage Vc when the capacitor charges
When capacitor is charging, q(t)=Qmax{1-e^[-t/(RC)]}, where q(t) is charge at time t, R is resistance and C is capacitance.
So, from the above equation , we know that if resistance R is increased, we will require longer time to reach Qmax. So, third option is correct.
Note that area under the curve represents total charge transferred which is same even if resistance value is changed. So , first option is not correct.
When discharging a capacitor,q(t)=Qmax*e^[-t/(RC)], where q(t) is charge at time t, R is resistance and C is capacitance. So, if resistance is increased, it takes more time to discharge the capacitor. So, second option is incorrect.
Also, Vc depends only on the external voltage supplied and not on resistance. So, fourth option is incorrect.
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