Question

Bruce Banner is trying to open a stuck door. He pushes it at a point 0.75 m from the hinges with a 240 N force direction 20 degrees away from being perpendicular to the door. There’s a natural pivot point, the hinges. What torque does Bruce exert?

Answer 1

Force Bruce exerts = F = 240 N

Angle of the force from the perpendicular to the door = = 20^o

Component of force acting perpendicular to the door = FCos

Distance of the point where the force is applied from the hinges = L = 0.75 m

Torque exerted by Bruce =

= (FCos)L

= (240)(0.75)Sin(20)

= 61.56 N.m

Torque exerted by Bruce = 61.56 N.m