A 44 kg block lies on a horizontal frictionless surface. A horizontal force of 110 N is applied to the block.
a) determine the acceleration of the block
b) calculate the distance the block will travel if the force is applied for 8 s.
c) calculate the speed of the block after the force has been applied for 8 s.
Mass of the block = m = 44 kg
Force applied on the block = F = 110 N
Acceleration of the block = a
F = ma
110 = (44)a
a = 2.5 m/s2
Time period the force is applied for = T = 8 sec
Initial speed of the block = V1 = 0 m/s
Speed of the block after 8 sec = V2
V2 = V1 + aT
V2 = 0 + (2.5)(8)
V2 = 20 m/s
Distance the block travels in 8 sec = D
D = V1T + aT2/2
D = (0)(8) + (2.5)(8)2/2
D = 80 m
a) Acceleration of the block = 2.5 m/s2
b) Distance the block will travel if the force is applied for 8 sec = 80 m
c) Speed of the block after the force has been applied for 8 sec = 20 m/s
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