Question

Calculate the de Broglie wavelength of **(a)** a
0.613 keV electron (mass = 9.109 × 10^{-31} kg),
**(b)** a 0.613 keV photon, and **(c)** a
0.613 keV neutron (mass = 1.675 × 10^{-27} kg).

Answer #1

Wavelength = h / p

p = m v = sqrt [2 m KE] = sqrt [2 * 9.11 * 10^{-31} *
0.613 * 10^{3} * 1.6 * 10^{-19}]

lambda = ( 6.63 * 10^{−34} ) / (1.34 * 10^{-23}
) **= 4.9 * 10 ^{-11} m**

--------------------------------------------------

b) Wavelength = h / p

p = m v = sqrt [2 m KE] = sqrt [2 * 1.675 * 10^{-27} *
0.613 * 10^{3} * 1.6 * 10^{-19}]

lambda = ( 6.63 * 10^{−34} ) / sqrt [2 * 1.675 *
10^{-27} * 0.613 * 10^{3} * 1.6 *
10^{-19}]

= **1.16 * 10 ^{-12} m**

---------------------------------------------------

c) Wavelength = h / p

p = m v = sqrt [2 m KE] = sqrt [2 * 1.675 * 10^{-27} *
0.613 * 10^{3} * 1.6 * 10^{-19}]

lambda = **1.16 * 10 ^{-12} m**

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