Question

How much moisture per pound of dry air is removed by air entering moist grain at 110 degrees F dry bulb temperature and exiting the grain at 90% RH and 68 degrees F wet bulb?

Moisture Removed = lbs H2O/lb DA

Answer #1

How much moisture per pound of dry air is removed by air
entering moist grain at 110 degrees F dry bulb temperature and
exiting the grain at 90% RH and 68 degrees F wet bulb?
Moisture Removed = lbs H2O/lb DA

How much moisture per pound of dry air is removed by air
entering moist grain at 110 degrees F dry bulb temperature and
exiting the grain at 90% RH and 68 degrees F wet bulb?

Find the increase in moisture per pound of dry air when going
from 42 degrees F dry bulb and 35 degrees F wet bulb to air with 72
degrees F dry bulb and 63 degrees F wet bulb.
Moisture Increase = ? lbs H2O/lbs DA

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