Question

A 16 g ice cube at -15.0oC is placed in 140 g of water at 48.0oC....

A 16 g ice cube at -15.0oC is placed in 140 g of water at 48.0oC. Find the final temperature of the system when equilibrium is reached. Ignore the heat capacity of the container and assume this is in a calorimeter, i.e. the system is thermally insulated from the surroundings. Give your answer in oC with 3 significant figures.

Specific heat of ice: 2.090 J/g K

Specific heat of water: 4.186 J/g K

Latent heat of fusion for water: 333 J/g

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Homework Answers

Answer #1

heat gained by ice = heat lost by the water

heat gained by ice = heat of water forced by ice + latent heat of fusion of ice

heat gained by ice = mass * specific heat * change in temperature + heat gained by ice from -15 degree to 0 degree + mass * latent heat of fusion

heat gained by ice = 16 * 4.186 * (T - 0) + 16 * 2.09 * (0 - (-15)) + 333 * 16

heat lost by water = 140 * 4.186 * (48 - T)

16 * 4.186 * (T - 0) + 16 * 2.09 * (0 - (-15)) + 333 * 16 = 140 * 4.186 * (48 - T)

T = 34.1497 degree C

equilibrium temperature = 34.1497 degree C

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