Question

The evaporation of sweat is an important mechanism for temperature control in some warm-blooded animals.

Part A What mass of water must evaporate from the skin of a 67.0 kg man to cool his body 1.05 ∘C? The heat of vaporization of water at body temperature (37.0 ∘C) is 2.42×106J/kg. The specific heat of a typical human body is 3480 J/(kg⋅K). Express your answer in kilograms. B:What volume of water must the man drink to replenish the evaporated water?

Answer 1

Then , m = 67.0 kg , Ch = 3480 J/kg.h

Then find mw = 101.6 g